S: Thrust vs Gravity & F22 Raptor

  • Thread starter Thread starter AstroNOT
  • Start date Start date
  • Tags Tags
    Gravity Thrust
AI Thread Summary
The F22 Raptor has a thrust-to-weight ratio of approximately 2:1, allowing it to climb vertically and hover, but it cannot continuously accelerate beyond a certain altitude due to gravity and drag. The force of gravity, approximately 9.8 m/s², limits its vertical acceleration as it ascends. As the aircraft climbs, the diminishing oxygen levels affect engine performance, reducing thrust and altering the thrust-to-weight ratio. While the Raptor can hover by overcoming gravity, it struggles against air resistance at high speeds. Ultimately, its ability to maintain acceleration is constrained by atmospheric conditions and engine efficiency.
AstroNOT
Messages
2
Reaction score
0
The F22 raptor has an approximate 2:1 thrust to weight ratio. It can climb vertically and stand on its tail in a hover.

Vertical acceleration is given by: Thrust - Drag - Weight = mass * acceleration (aka gravity). The opposing force to thrust involves an acceleration due to the force of gravity which is roughly equal to 9.8 m/s/s. So a 2:1 thrust ratio, though fun, cannot overcome the force of gravity i.e. accelerate continually -- in which case the craft would reach escape velocity which is in excess of 11 km/s or in the vicinity of mach10.​

Please advise about any misinformation here. As well as the mechanics that keep this craft from accelerating beyond 70k feet. How does one conceptualize per second per second acceleration? Distance per second is conceivable. Acceleration is observable. But the designation escapes me.

Thanks for any advice.
AstroNOT
 
Last edited:
Physics news on Phys.org
That paragraph doesn't make a whole lot of sense. At a 2:1 thrust ratio, a plane will accelerate vertically until drag slows the acceleration and then will decelerate as the engines lose thrust at high altitude.

I'm not sure I understand your question in the last part. m/s/s is the units of acceleration.
 
At the very least, it shouldn't really be too hard to concieve of the units of acceleration. Meters per second per second means how many (meters per second) it gains every second.
 
Acceleration is the change of velocity per second. For example in the case of gravity, acceleration indicates a change in velocity of 32 ft/sec each second.

For constant vertical acceleration, the jet aircraft would require constant atmosphere. As the aircraft climbs, the presence of oxygen diminishes and dramatically affects engine output. Combustion efficiency depends on cool dense atmosphere. High altitude flight affects turbine engines and decreases thrust, altering the thrust to weight ratio and acceleration.
 
Conceptionalise acceleration in terms of gravity. For example, you might say the raptor has 2 g's of acceleration. It can overcome the force of gravity (which means to hover), it just can't overcome the force of air resistance pressing against it at a few times the speed of sound or beyond. Also, it can't fly without the atmosphere, which (ignoring limited fuel supplies) is the only reason helicopters can't just slowly inch their way to outer space.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top