Sailboat Acceleration Calculation

AI Thread Summary
The discussion focuses on calculating the initial acceleration of a 950-kg sailboat under a 15-knot wind. The force from the wind is perpendicular to the sail and depends on the wind's velocity component. Water provides a stabilizing force along the keel, preventing sideways movement, while also creating drag that opposes forward motion. Participants emphasize using vector components to analyze the forces acting on the sailboat. The conversation encourages applying the formula F = ma to determine the boat's initial acceleration.
DriverX
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Initial Acceleration?

The force exerted by the wind on a sailboat is approximately perpendicular to the sail and proportional to the component of the wind velocity perpendicular to the sail. For the 950-kg sailboat shown in the figure below, the proportionality constant is
da.gif


Water exerts a force along the keel (bottom) of the boat that prevents it from moving sideways, as shown in the figure. Once the boat starts moving forward, water also exerts a drag force backwards on the boat, opposing the forward motion.

If a 15-knot wind (1 knot = 0.514 m/s) is blowing to the east, what is the initial acceleration (m/s2) of the sailboat?

diagram.gif
 
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Welcome to PF!

Hi DriverX! Welcome to PF! :smile:

But … is that picture really a sailboat? :confused:

It looks more like a horse! :biggrin:
 


p4-54.gif
 
that's better! :biggrin:

ok …
DriverX said:
The force exerted by the wind … is … proportional to the component of the wind velocity perpendicular to the sail.

… so find the force exerted by the wind perpendicular to the sail, and so find the forward force, and use F = ma.

What do you get? :smile:
 


Driver
because a force is a vector and the question is in two dimensions, i.e X and Y,
you can separate the force into it's x and y components

e.g if you push a block north east (like your sail) at an angle of 45 degrees
your F vector, is really two forces, one going east in the X direction, and one going north in the Y direction,

so the Feast = Fcos45 degrees
and Fnorth = Fsin45 degrees

you can use this concept (i think? ) to help solve your question
 
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