Conservation of Energy and Angular Momentum in a Satellite Breakup

AI Thread Summary
In the discussion on the conservation of energy and angular momentum during a satellite breakup, participants analyze the scenario where a satellite with mass m splits into two equal parts, each with mass m/2. The key focus is on determining the total energy and angular momentum of the resulting fragments immediately after the breakup. It is clarified that while the fragments move radially apart in the satellite's frame, their actual motion relative to the planet includes both radial and tangential components. The original tangential velocity v remains unchanged, while the radial velocity v0 is introduced for the separation of the parts. The conversation emphasizes the importance of distinguishing between these velocities to correctly apply conservation principles.
peripatein
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Hi,

Homework Statement


A satellite with mass m orbits a planet of mass M in a circular path with radius r and velocity v. Due to some internal technical failure, the satellite breaks into two, similar parts with mass m/2 each. In the satellite's frame of reference, it appears the two parts move radially, in opposite directions, along the line connecting the original satellite and the planet's center, each with velocity v0/2. I am expected to show that right after the technical failure, each of the two parts has a total energy equal to -3GM/16r and angular momentum equal to (m/2)√(GMr), wrt the planet's center.


Homework Equations





The Attempt at a Solution


The total energy of each of the two parts should be, I believe: Etot = mv02/16 - GmM/(2r). Now, isn't angular momentum preserved despite the failure? However, why isn't the angular momentum zero if the two parts are moving in opposite directions?
 
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hi peripatein! :smile:
peripatein said:
Now, isn't angular momentum preserved despite the failure?

yes :smile:
However, why isn't the angular momentum zero if the two parts are moving in opposite directions?

you're misreading the question …

they are moving in opposite directions in the rest-frame of the satellite

imagine a rod moving sideways, and two beads moving with equal speeds away from each other along it …

the actual motions of the beads are both diagonally forwards :wink:
 
The velocity of the the CoM remains v, right? And I know that wrt that CoM, each part moves at +-v0/2, right? Ergo, the velocity of each part wrt to the planet's center should be the sum of the CoM's velocity (which I know) and the velocity of the respective part wrt the CoM (which I also know), correct?
 
yes.
 
Don't I need some sort of relation between v and v0? I am unable to obtain that through conservation of angular momentum though.
 
i think vo and v are suposed to be the same
 
tiny-tim said:
i think vo and v are suposed to be the same

No. v is the original tangential velocity. v0 is the radial velocity with which the two move apart.
 
peripatein said:
The total energy of each of the two parts should be, I believe: Etot = mv02/16 - GmM/(2r).
They also have the KE of the original tangential velocity, v.
 
tiny-tim said:
i think vo and v are suposed to be the same
haruspex said:
No. v is the original tangential velocity. v0 is the radial velocity with which the two move apart.

i think vo and v are supposed to be the same :smile:
 
  • #10
tiny-tim said:
i think vo and v are supposed to be the same :smile:
Ah, you mean equal, which is not quite the same as same :biggrin:.
 
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