Satellite Velocity Homework: Calculate Distance, Acceleration, and Speed

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Homework Help Overview

The discussion revolves around a satellite's orbital mechanics, specifically focusing on calculating the distance above Earth's surface, the acceleration of the satellite, and the required speed to maintain its orbit. The gravitational field strength at the satellite's altitude is given as 4.5 N/kg.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants explore the relationship between gravitational force and orbital parameters, questioning the calculations for distance, speed, and acceleration. There is an attempt to verify the calculations and clarify the meaning of gravitational field strength in terms of acceleration.

Discussion Status

Some participants have provided feedback on the calculations, particularly regarding the speed and the interpretation of gravitational field strength. There is ongoing exploration of how to determine the acceleration and its direction, with some participants expressing uncertainty about the information provided by external sources.

Contextual Notes

Participants are working within the constraints of the problem as presented, including the specific values for Earth's mass and radius, and the gravitational field strength. There is a noted lack of clarity regarding the direction of acceleration and the implications of the given gravitational strength.

AClass
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Homework Statement



A satellite is designed to orbit Earth at an altitude above its surface that will place it in a gravitational field with a strength of 4.5 N/kg.

a) Calculate the distance above the surface of Earth at which the satellite must orbit.

b)Assuming the orbit is circular, calculate the acceleration of the satellite and its direction.

c)At what speed must the satellite travel in order to maintain this orbit?

mass of Earth : 5.98 x 10^24 kg
radius of the Earth : 6.38 x 10^6 m

Homework Equations



Fg= G mE / r^2
ac=v^2/r
v= sqrt ( GmE/r )
ac= 4Pi^2 r / T^2


The Attempt at a Solution



a)
4.5N/Kg=G(5.98x10^24kg)/r^2

r=9.4168x10^6m

h=re-r=3.0x10^6

Distance above the surface at which the satellite must orbit is 3.0x10^6m.

b)

No clue, I have searched many resources and they fail to give any clear ideas on how to tackle this question.

c)

Using

v=sqt(GMe/r)
v=sqt(G(5.98x10^24kg)/9.4168x10^6)
v=6.5097x10^6 m/s

Seems a bit too much. Could someone verify c) and I would appreciated any help with b), also verification of a) but I think I got it.
 
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AClass said:
v=sqt(GMe/r)
v=sqt(G(5.98x10^24kg)/9.4168x10^6)
v=6.5097x10^6 m/s

Seems a bit too much. Could someone verify c) and I would appreciated any help with b), also verification of a) but I think I got it.

Check your math for (c). You may have slipped up on the exponents.

For (b), consider N/kg by another name...
 
gneill said:
Check your math for (c). You may have slipped up on the exponents.

For (b), consider N/kg by another name...

c)
v=sqt(GMe/r)
v=sqt(G(5.98x10^24kg)/9.4168x10^6)
v=6509.6776m/s
I had forgotten to take the square root.

for b)

Other sources suggested that 4.5N/Kg is equal to 4.5m/s^2, that being its only acceleration. Seems that someone else who has taken my course before had confirmed that 4.5m/s^2 is not the correct acceleration.

I believe finding the acceleration from centreifual, and circular motions is my best bet.

However, I'm limited in terms of variables.
 
I suspect that 'other sources' failed to provide a direction for the acceleration.
 
gneill said:
I suspect that 'other sources' failed to provide a direction for the acceleration.

Yes, they failed to provide a direction. All that was explained is in the direction towards the earth.
 

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