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Scalar potential and line integral of a vector field

  • Thread starter alecst
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  • #1
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Homework Statement



nSlbe.png


Homework Equations



Given above.

The Attempt at a Solution



I attempted this problem first without looking at the hint.

I've defined F(r) as (B+A)/2 + t(B-A)/2, with dr as (B-A)/2 dt . Thus F(r)dr = ((B+A)/2)*((B-A)/2)+((B-A)/2)^2 dt

When I integrate this from -1 to 1 I get 1/2*(B^2-A^2).

When I then looked at the hint, I saw it mentioned another (B^2+A^2)/2 term and another "c," neither of which I have, and my integrand has no "tau" squared element either. Is there a point where I went wrong here?
 

Answers and Replies

  • #2
LCKurtz
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I'm guessing that you don't get to define F(r) but instead have to use the one given to you in problem 4.01, whatever that is.
 
  • #3
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The idea is to used the derived formula to solve the next problem, which is find a scalar potential function phi(r) such that the line integral F(B,A) (as in 4.02) = phi(B)-phi(A). So it's clear I need to solve this in terms of B and A.
 

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