Scalar product to prove triangle inequality?

AI Thread Summary
To prove the triangle inequality |a+b| <= |a| + |b| using the scalar product, begin by expressing |a+b|^2 as (a+b)·(a+b). Expanding this gives |a|^2 + |b|^2 + 2(a·b). Utilize the inequality |a·b| <= |a||b| to bound the term 2(a·b). This leads to |a+b|^2 <= |a|^2 + |b|^2 + 2|a||b|, which simplifies to |a+b| <= |a| + |b| upon taking the square root. The triangle inequality is thus established.
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Homework Statement


From the inequality

|a.b| <= |a||b|

prove the triangle inequality:

|a+b| <= |a| + |b|

Homework Equations



a.b = |a|b| cos theta

The Attempt at a Solution



Making a triangle where side c = a+b. Don't know how to approach the question.

Thanks.
 
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I may not be understanding your question, but it seems like you should start with the Pythagorean Identities.
 
Also think about what values your trig function is between
 
You should start by knowing |a+b|^2=(a+b).(a+b). Now expand the right side.
 
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