Second order DE in matrix form

teapsoon
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Homework Statement



Consider the differential equation \bold{x}'=\left[ \begin{array}{cc} -1 & 2 \\ -1 & -3 \end{array} \right]\bold{x}, with \bold{x}(0)=\left[ \begin{array}{c} 1 \\ 1 \end{array} \right]

Solve the differential equation where \bold{x}=\left[ \begin{array}{c} x(t) \\ y(t) \end{array} \right].

solving for the x vector and y vector

Homework Equations





The Attempt at a Solution

 
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teapsoon said:

Homework Statement



Consider the differential equation \bold{x}'=\left[ \begin{array}{cc} -1 & 2 \\ -1 & -3 \end{array} \right]\bold{x}, with \bold{x}(0)=\left[ \begin{array}{c} 1 \\ 1 \end{array} \right]

Solve the differential equation where \bold{x}=\left[ \begin{array}{c} x(t) \\ y(t) \end{array} \right].

solving for the x vector and y vector

Homework Equations





The Attempt at a Solution


I added [ tex] and [/ tex] tags (without leading spaces inside the brackets).

What have you tried? Do you have any ideas for how you might solve this system of equations?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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