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Second order differential equation - Drawing circuit

  1. Nov 19, 2013 #1
    The problem statement, all variables and given/known data

    "Solve differential equation y''+y=2*cos x. Draw circuit of the equation and think about the strange behavior of the current."

    The attempt at a solution

    I was able to solve the equation, but I have no idea how to draw circuit about it, we haven't gone
    through this at lessons.

    Solution:

    y(x)=C_1*e^(ix)+C_2*e^(-ix)+x*sin x
     
  2. jcsd
  3. Nov 19, 2013 #2

    Mark44

    Staff: Mentor

    For the drawing part, think about what the coefficients of the DE mean in regard to the capacitor, coil, and resister of an LRC circuit. Since there's no y' term, one of these components is missing in your circuit.

    For your solution, you have eix and e-ix as the basic functions that are the solutions to the homogeneous problem. You could also have used cos(x) and sin(x). Since eix = cos(x) + i*sin(x), and e-ix = cos(x) - i*sin(x), it's not too hard to find that cos(x) = (eix + e-ix)/2 and something similar for sin(x).
     
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