Second order differential equations

fan_boy17
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Homework Statement



finding the general solution. I would like to know if the 20-e^x will be treated as a sum of a polynomial?

Homework Equations





The Attempt at a Solution

 

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fan_boy17 said:

Homework Statement



finding the general solution. I would like to know if the 20-e^x will be treated as a sum of a polynomial?

Homework Equations





The Attempt at a Solution


20 - ex is not a polynomial. A search on wikipedia will turn up the definition of a polynomial.
 
It is, of course, the sum of two functions. Did you really mean to say "polynomial"?

You should look for a "particular solution" of the form A+ Bex.
 
HallsofIvy said:
It is, of course, the sum of two functions. Did you really mean to say "polynomial"?

You should look for a "particular solution" of the form A+ Bex.

That's a typo, Halls meant ##A+Be^{2x}##.
 
can anyone help with solving it :(
 
fan_boy17 said:
can anyone help with solving it :(

What are you stuck on? Have you solved the associated homogeneous equation for its general solution ##y_c##? Have you tried looking for a particular solution of the NH equation of the form ##y_p=A + Be^{2x}## as has been suggested? It is all straightforward. Show us what you have so far.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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