Separable differential equations

[/B]

The Attempt at a Solution

I've highlighted two equations on the screenshot. How did it proceed from the first to the second? I'm actually confused with the absolute values. What is the idea behind getting rid of the first absolute value(1-5v^2) while keeping the second one(x)?

Answers and Replies

Related Calculus and Beyond Homework Help News on Phys.org
RUber
Homework Helper
So for starters, the manipulation is something like:
##-\frac 15 \ln | 1 - 5v^2 | = \ln |x| + c ##
##\begin{align*}
\ln | 1 - 5v^2 | &= -5(\ln |x| +c)\\
&= -5( \ln |x| - \ln e^{c} )\\
&=-5 ( \ln \frac{|x|}{e^{c} })\\
&= \ln \left(\frac{|x|}{e^{c} }\right)^{-5} \\
&= \ln \left(\frac{e^{5c} }{|x|^5}\right) \end{align*}##
Then, removing the absolute value from the left gives: ##1-5v^2 = \pm \left(\frac{e^{5c} }{|x|^5} \right) ##
So ##C = \pm e^{5c} ##
There only reason not to take out the absolute value from x that I can see is so that C is not dependent on x.

Dr. Courtney
Education Advisor
Gold Member
You get rid of the ln by exponentiating both sides.