Separable Equation with Condition?

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SUMMARY

The discussion focuses on solving a separable differential equation with the initial condition y(2) = 2. The equation is transformed into the form \(\frac{dy}{y+3} = \frac{t}{t^2+1}dt\) after factoring. Participants confirm that y(2) = 2 serves as an initial condition, allowing for the determination of the arbitrary constant after integration. The solution process is straightforward once the equation is properly separated and integrated.

PREREQUISITES
  • Understanding of separable differential equations
  • Knowledge of integration techniques
  • Familiarity with initial conditions in differential equations
  • Basic algebra for factoring expressions
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  • Practice solving additional separable differential equations
  • Explore techniques for integrating rational functions
  • Study the role of initial conditions in determining unique solutions
  • Learn about the implications of arbitrary constants in differential equations
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Students studying differential equations, mathematics educators, and anyone seeking to enhance their problem-solving skills in calculus.

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[SOLVED] Separable Equation with Condition?

Homework Statement


Solve.
http://www.mcp-server.com/~lush/shillmud/int3.71.JPG

Homework Equations



The Attempt at a Solution


I'm not sure how to separate this. Also, since the directions consist of only one word, I'm not sure if y(2)=2 is some kind of hint or an additional condition to be fulfilled. I'm wondering where to go after factoring t out of the top. Thanks.
http://www.mcp-server.com/~lush/shillmud/int3.72.JPG
 
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Well after factoring... you separate (hence separable equations!)

\frac{dy}{y+3} = \frac{t}{t^2+1}dt

Then integrate both sides.
y(2) = 2 is an initial condition, not a hint... After solving for y(t) you will have one arbitrary constant, which can be solved for using this condition.
 
Wow, that seems almost too easy. Thanks.
 

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