Seperation effects on the forces of gravity and eletricity

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SUMMARY

The discussion centers on the comparison of gravitational and electrical forces when two charged pellets are separated to twice their original distance. It is established that the electrical force, calculated using Coulomb's law with the constant K (8.987 x 10^9), is significantly larger than the gravitational force, which uses Newton's law of gravitation with the constant G (6.673 × 10−11). When the distance is doubled, the electrical force decreases by a factor of four, while the gravitational force also decreases by the same factor, confirming that the electrical force remains dominant in typical scenarios involving charged particles.

PREREQUISITES
  • Understanding of Newton's law of gravitation (Fg = (G x m1 x m2) / r²)
  • Familiarity with Coulomb's law for electrical force (Fe = (K x q1 x q2) / r²)
  • Basic knowledge of the constants G and K
  • Concept of force variation with distance in physics
NEXT STEPS
  • Explore the implications of gravitational and electrical forces in different mass and charge scenarios
  • Investigate the role of distance in force calculations using both gravitational and electrical equations
  • Learn about the significance of constants G and K in real-world applications
  • Examine the effects of varying charge and mass on force interactions
USEFUL FOR

Students studying physics, educators teaching force interactions, and anyone interested in the comparative analysis of gravitational and electrical forces.

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Homework Statement


Two charged pellets are pulled apart to twice their original separation. (a) Which is likely to be larger, the gravitational force or the electrical force between them? Why? (b) Which will change by a greater factor when they are pulled apart, the gravitational force or the electrical force between them? Why?


Homework Equations


Fg = (G x m1 x m2) / r2
Fe = (K x q1 x q2) / r2


The Attempt at a Solution


a) Well, assuming 6.673 × 10−11 for the constant of G and 8.987 x 10 9 for the constant of K, I would assume that the electrical force would be higher.
b) I am assuming that they would change at the same factor when they are pulled apart.

Am I assuming correct or am I wrong?
 
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gravitational force is immmmmmmensely SMALLER than the electrical force.

remember, unless you are working with an extremely large mass, the electrical force will always be larger. plug in your value for mass and charge into the two force equations.
 
This type of question basically asks you what happens to the force when the distance is doubled. To see it, write
Fe = (K x q1 x q2) / r2
and then write it again replacing r with (2r). Do it with a red 2 if you can. Then you try to factor the 2 out so it sits in front of the rest of the stuff. In this case you'll get
Fe2 = (K x q1 x q2) / (2r)2 = 1/2^2*(K x q1 x q2) / r2 = 1/4*Fe
showing that the new force at double the distance is 1/4 of the original force.
 

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