Infinity Sum: Solving Sequences with Sin n(pi) / 6

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The discussion focuses on solving the infinite sum of the sequence sin(nπ)/6 for n starting from 1. Participants suggest computing the first few values and partial sums to identify a pattern or formulate a guess about convergence. It is confirmed that since all terms of the sequence equal zero, the sum converges. The conversation emphasizes the importance of analyzing the sequence's behavior to understand its convergence properties. Overall, the sequence converges to zero.
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hiw to solve for infinity sum (n=1) [sin n(pi)] / 6 ??
pls help...thanx
 
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Do you mean how to compute that sum? Have you tried writing out its first few values and computing the first few partial sums, to try and formulate a guess?
 
all equals to zero and converges right??
 
If all the terms sums are zero, then yes, it will converge!
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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