Sequences ratio test, intro to real analysis

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Homework Statement



Let X = (xn) be a sequence of positive real numbers such that lim(xn+1 / xn) = L > 1.


Show that X is not a bounded sqeuence and hence is not convergent.


Homework Equations


Definition of convergence states that for every epsilon > 0 there exist some natural number K such that for all n > = K, |xn - x| < epsilon, then the squence converges to x.


The Attempt at a Solution



This is a proof so there really isn't too much to say here. I have looked at the definition of convergence and I see that I can get something like xn+1 < xn(L+e) where e is epsilon, but I do not see any way to produce an upper bound from that. I also know that the previous statement is true for all e, but that still does not seem to get me anywhere. I know I need to use the fact that L > 1, but I don't see how at this point.


Any hints, subtle or not, are welcome.

Thanks,

The Geekster
 
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Use epsilon=(L-1)/2. That means for some N, for all n>N. x_n+1>((L+1)/2)*x_n. (L+1)/2>1. So for n>N x_n increases at least as fast as a power series with a ratio > 1.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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