The question:Rewriting Series with Sigma Notation

AI Thread Summary
The discussion revolves around expressing the series 1 - 2 + 4 - 8 + 16 - 32 in sigma notation. The original answer provided by the user, \sum_{0}^5 -2^r, is incorrect because it results in all negative terms. The correct representation is \sum_{k=0}^{5}(-2)^{k}, which accurately captures the alternating signs of the series. The confusion stemmed from misunderstanding the placement of negative signs and the use of parentheses in the expression. The user acknowledges the mistake and expresses gratitude for the clarification.
Mo
Messages
81
Reaction score
0
Series and "Sigma" Notation

I have been revising over the sigma/sequences and series chapters, this is the second question now where i have had different answers to the book - yet- my answers seem to work - i think...

The question :

Write in \sum notation

1 - 2 + 4 - 8 + 16 - 32


My answer is:

\sum_{0}^5 -2^r

Is this correct?

Thie answer in the book by the way is:

\sum_{1}^6 (-1)^{r+1} \ 2r^{r-1}

Regards,
Mo
 
Physics news on Phys.org
Mo said:
I have been revising over the sigma/sequences and series chapters, this is the second question now where i have had different answers to the book - yet- my answers seem to work - i think...

The question :

Write in \sum notation

1 - 2 + 4 - 8 + 16 - 32


My answer is:

\sum_{0}^5 -2^r

Is this correct?
...

Nope. Every term in that sum is negative (which is not true for 1 - 2 + 4...).
 
Then the answer in the books seems wrong and yours as well.
1-2+4-8+16-32=(-)^{0}2^{0}+(-)^{1}2^{1}+(-)^{2}2^{2}+(-)^{3}2^{3}+(-)^{4}2^{4}+(-)^{5}2^{5}=\sum_{k=0}^{5}(-)^{k}2^{k}

You might have mistyped the answer in the book.

Daniel.
 
Yes i have typed in ther answer from the book wrongly, very sorry about that.

\sum_{1}^6 (-1)^{r+1} \ 2^{r-1}

is the correct one.

However i still can't see how my answer is wrong!

when r is 0 , the answer is +1
when r is 1 , the answer is -2
when r is 2 , the answer is +4
when r is 3 , the answer is -8

so this would mean +1-2+4-8 ? Or maybe I am making a really stupid mistake here!

Thanks for your replies so far!
 
Mo said:
However i still can't see how my answer is wrong!

when r is 0 , the answer is +1
when r is 1 , the answer is -2
when r is 2 , the answer is +4
when r is 3 , the answer is -8

so this would mean +1-2+4-8 ? Or maybe I am making a really stupid mistake here!

Thanks for your replies so far!

At first, I thought your answer was right. It's not, cos your sum is -2^r and not (-2)^r. When r is 0, for your answer, you get -1, ie. -1 x 2^0.
 
Your answer would have been correct if you would have used this one: -

The following code was used to generate this LaTeX image:



\sum_{k=0}^{5}(-2)^{k}
 
Look at it this way: If you had

\sum (1-2^r)

would you say that was

(1-1) + (1-2) + (1-4) + ...

or

(1+1) + (1-2) + (1+4) + ...

?

When you evaluate an expression that doesn't have parentheses inside of it, and is on a single line, exponents always come first, then multiplication/division, then addition/subtraction.
 
Thank you for your replies all

Offcourse i should have used brackets :sigh: next time ill remember!

thanks again

Regards,
Mo

PS: JTbell, this first one ..
 
I just realized that I got the signs backwards on my second choice.

Oh well, you got the right idea, anyway!
 

Similar threads

Back
Top