What is the total charge in a series capacitor circuit?

AI Thread Summary
In a series capacitor circuit, each capacitor holds the same charge, which is also the charge of the effective capacitor that can replace the entire array. The total charge in the circuit is equal to the charge on one capacitor, not the sum of charges from multiple capacitors. This is because the intermediate plates' charges cancel each other out, resulting in a net charge of zero across the entire series. The effective capacitor's charge reflects this uniformity among the capacitors. Understanding this concept clarifies the behavior of charge in series capacitor arrangements.
Jamessamuel
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Hello,
So in a series capacitor arrangement, I understand that the charge on each capacitor is the same. I also appreciate that you can replace the array with an effective capacitor. What I am not in agreement with is the fact that the charge on this effective capacitor is the same as the charge on one of the capacitors. Surely if they all have accumulated the same amount of electrons than you should multiply the number of capacitors by this amount to get the effective charge. What is being said to me is that the total charge In the circuit is equal to the charge on one capacitor?!

Please rescue me from this conceptual calamity.
 
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Yeah, that doesn't sound right. What they probably mean is that the charges are the same as that *one* effective capacitor.
 
You do realize that the net charge on that string of capacitors, including all plates, would be zero? Consider the plates at either end of the string of capacitors: those are the plates of the equivalent capacitor. (The charge on the intermediate plates all cancels out.)
 
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