damoj
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basically i have to check if
xln\frac{(x+1)}{x}→ 1 as x→∞
the first term is 0 as x→∞
in the answers they say they used maclaurin series and got
x(\frac{1}{x} + O\frac{1}{1^{2}})
but don't show how they did it.
would the first term in the series be
a(ln(\frac{a+1}{a}))
there a = 0, but then the ln function is defined?
im getting a little confused about have a=0 but we want to figure out where the function goes to as x→∞
xln\frac{(x+1)}{x}→ 1 as x→∞
the first term is 0 as x→∞
in the answers they say they used maclaurin series and got
x(\frac{1}{x} + O\frac{1}{1^{2}})
but don't show how they did it.
would the first term in the series be
a(ln(\frac{a+1}{a}))
there a = 0, but then the ln function is defined?
im getting a little confused about have a=0 but we want to figure out where the function goes to as x→∞