Series parallel combination circuit

AI Thread Summary
The discussion revolves around calculating the total resistance, current at I1, voltage over R6, and current through I5 in a circuit diagram. The total resistance was initially calculated as 12 Ohms, with I1 at 1A and R6 at 6V. Participants emphasized the importance of identifying resistors in series and parallel and applying Kirchhoff's laws to derive equations for the currents. There was confusion regarding the impact of resistor R3, which was suggested to be short-circuited and thus not contributing to the total resistance. Clarifications were provided about the circuit's configuration and the role of shorted resistors in simplifying calculations.
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Homework Statement



In the attached circuit diagram, I have to find the Total resistance of the cicuit, the current at I1, the voltage over R6 and the current through I5.

Homework Equations



V = IR

The Attempt at a Solution



Rt = 12Ohms
I1 = 1A
R6 = 6v
I5 = 1A

Homework Statement

 

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Figure out which resistors are in series and which are in parallel. Then,try using a combination of kirchoff''s loop and junction rules to come up with a few linearly independent equations from which you can solve for the various I's. Also, Ohm's law is V = IR. See where that gets you.
 
Hello,

I re-attached my attempt, please have a look. I need to solve for the total resistance, current through I1, voltage over R6, and current through I5. I made an attempt by reducing the circuit to a simpler circuit. What confuses me is the current through I5, and whether R3 actually makes any difference to the total resistance of the circuit, because in my eyes it is as if it is bypassed by the wire carrying current I5.

Meant V = IR, sorry about that.

Help will be much appreciated. Thanks
 
Could you tell me what the resistance of the top right resistor is? It's not included in the diagram.
 
Its 24 Ohm, I re-scanned the diagram, has all info now..
 
Well, are you familiar with Kirchoff's loop rule?
 
I know his First law(current law), and Second law(Voltage law). Are you talking about one of them?


Just another question, if Resistor three is short circuited, does it add to the total resistance of the circuit or do I just ignore it?
 
Well, the loop rule states that the sum of all the potential differences around a closed circuit is zero (For a conservative electric field that is). Have a think about that in relation to the total resistance of your circuit.
 
Uhhh... I think I am a little confused now. But ill try to figure it out.. Thanks for the help
 
  • #10
Wait, I've totally jumped the gun here with using the rules. My apologies for any confusion!
 
  • #11
Hint: R4 the 10Ω resistor is shorted, it does not contribute anything. Remove it from the circuit all currents and voltages will remain the same.
 
  • #12
Integral said:
Hint: R4 the 10Ω resistor is shorted, it does not contribute anything. Remove it from the circuit all currents and voltages will remain the same.
Actually that's R3.
 

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