What is the Power Factor of a Series RCL Circuit at 2520 Hz?

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The discussion centers on calculating the power factor of a series RCL circuit with a 47.0-ohm resistor, a 2.00 µF capacitor, and a 5.00 mH inductor at a frequency of 2520 Hz. The power factor is defined as the cosine of the phase angle, which is influenced by the phase difference between the inductor and capacitor voltages. At resonance, the phase difference is 90 degrees, resulting in a power factor of zero, indicating no power dissipation. However, when considering the resonance condition where the inductor and capacitor cancel each other, the power factor can be one, meaning all source voltage is across the resistor. This highlights the importance of resonance in maximizing power dissipation in the circuit.
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Homework Statement


A series RCL circuit contains a 47.0 resistor, a 2.00 µF capacitor, and a 5.00 mH inductor. When the frequency is 2520 Hz, what is the power factor of the circuit?


Homework Equations


cos(angle)=Vr/Vo
Vr=(IrmsR)
Vo=IrmsZ


The Attempt at a Solution


I know power factor is the cos(angle), but I'm having trouble figuring out what this question is actually asking for
 
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i bet that the power factor is just the phase difference btw inductor and capacitor voltages : )
 
at resonance the power dissipation is maximum (i mean if the source resistance is matched to R).. and the phase difference btw C and L voltages is 90 degrees. which makes a power factor of cos90 = 0?
 
ok i get it know theta is defined as (pi/2 - phi). phi being the phase difference btw C and L voltages. and at resonance, phase difference is pi/2 and that makes power_factor = 1 = Vr/Vo, which implies that all of the source voltage (Vo) is observed on the resistance (Vr), which was expected, since at resonance C and L cancels each other.
 

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