Setting up binary star (light density based on distance) problem

oogabuga
Messages
1
Reaction score
0
For my vector calc class we were given an assingment to do some stuff with a binary star system. You might note the lack of vectors and the lack of calc; this is because I am just having an issue with the setup. I am sure I can get the rest without assistance.

We are given the two stars of equal light intensity. One at the origin and the other at (0,0,14).

The light intensity 'L' at a point 'P' is given with L=(1/(D1^2))+(1/(D2)^2), where D1 and D2 are the distances from the two stars.

So what is a formula for L in rectangular coordinates (x,y,z)?

I tried playing around with with the equation for an ellipsoid for a while but that seemed fruitless. Also a sphere (with rad = sqrut(D1^2+D2^2), but gave up on that.

Any pointers? If you are feeling ambitious I will also need to find this is spherical coordinates, but I have yet to play with that myself...
 
Physics news on Phys.org
Well what is D1 and D2 in rectangular coordinates? Draw a graph and put the two stars on it. Then put a random point on the graph at (x_0, y_0,z_0). To find D_1 draw a vector from the origin (where star 1 is) to the point. What is the magnitude of this vector? To find D_2 draw a vector from (0,0,14) (star 2) to (x_0,y_0,z_0). What is the magnitude of this vector?
 
Last edited:
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top