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shorti2406
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Q: The prong of a tuning fork moves back and forth when it is set into vibration. The distance the prong moves between its extreme positions is 2.29 mm. If the frequency of the tuning fork is 440.2 Hz, what are the maximum velocity and the maximum acceleration of the prong? Assume SHM.
I was just hoping somebody could tell me if I did this problem correctly
For Vmax I have : (2л) x (440.2Hz) x (0.0029cm) = 8.02 m/s
For amax I have : [(2л x 440.2Hz)^2] x (0.0029cm) = 22185 m/s2
I would appreciate any input! Thanks!
I was just hoping somebody could tell me if I did this problem correctly
For Vmax I have : (2л) x (440.2Hz) x (0.0029cm) = 8.02 m/s
For amax I have : [(2л x 440.2Hz)^2] x (0.0029cm) = 22185 m/s2
I would appreciate any input! Thanks!