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SHM two-block spring system

  1. Nov 29, 2012 #1
    Two blocks (m=1.0 kg and M=10 kg) and a string (k=200 N/m) are arranged on a horizontal, frictionless surface (in the picture m rests atop M). The coefficient of static friction between the two blocks is .40. What amplitude of simple harmonic motion of the spring-blocks system puts the smaller block on the verge of slipping over the larger block?

    acom=F/(mA+mB)

    F=-kAcos(ωt) and ω=√(k/(mA+mB)= 4.26

    so F=-200Acos(4.26t)

    acom=-200Acos(4.26t)/11
    =-18.2Acos(4.26t)

    This is all I got so far. What I am confused about is that μk is not given. So isn't it impossible to figure out the acceleration of the top block once static friction is overcome? I also am not given the lengths of the blocks.
     
  2. jcsd
  3. Nov 29, 2012 #2

    haruspex

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    The question means, at what amplitude would it start to slip? For that you only need static friction coefficient, and the block widths are irrelevant.
     
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