- #1
sigh1342
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shooting method for non-linear equation(urgent)
for shooting method , in non-linear equation, we're find
$$t_{k}=t_{k-1}-\frac{[y(b,t_{k-1})-β](t_{k-1}-t_{k-2})}{y(b,t_{k-1})-y(b,t_{k-2})}$$
but how can we find the $$y(b,t_{k})$$ ?
I am suppose to use Euler method for it , but I'm confused,
for example , the question is $$y''=-(y')^2-y+lnx , 1≤x≤2 , y(1)=0, y(2)=ln2$$
suppose $$t_{0}=3, y(2,t_{0})=2.775, t_{1}=0.7, y(2,t_{1})=0.5775 $$we can find $$t_{2}=0.72105$$ then how can we find $$y(2,t_{2})$$ ?with Euler method , with h=0.5,
and I also want to know if the question didn't give what the $$y(b,t_{0})$$ , and $$y(b,t_{1})$$ is , how can I find them in the case , I know what $$t_{0} $$ and $$t_{1}$$ is , sorry for the poor
English but the way.
Homework Statement
for shooting method , in non-linear equation, we're find
$$t_{k}=t_{k-1}-\frac{[y(b,t_{k-1})-β](t_{k-1}-t_{k-2})}{y(b,t_{k-1})-y(b,t_{k-2})}$$
but how can we find the $$y(b,t_{k})$$ ?
I am suppose to use Euler method for it , but I'm confused,
for example , the question is $$y''=-(y')^2-y+lnx , 1≤x≤2 , y(1)=0, y(2)=ln2$$
suppose $$t_{0}=3, y(2,t_{0})=2.775, t_{1}=0.7, y(2,t_{1})=0.5775 $$we can find $$t_{2}=0.72105$$ then how can we find $$y(2,t_{2})$$ ?with Euler method , with h=0.5,
and I also want to know if the question didn't give what the $$y(b,t_{0})$$ , and $$y(b,t_{1})$$ is , how can I find them in the case , I know what $$t_{0} $$ and $$t_{1}$$ is , sorry for the poor
English but the way.