Short Question about improper integrals:

  • Thread starter Thread starter Edwardo_Elric
  • Start date Start date
  • Tags Tags
    Integrals Short
Edwardo_Elric
Messages
101
Reaction score
0
Hi

I was Just hoping to ask a short question about improper integrals ...

when there are two limits in the integral: the 1st limit is divergent but the second limit is indeterminate... can it be automatically divergent? or do you need to evaluate first the second limit using LHR? so that both limits becomes divergent
 
Physics news on Phys.org
if it has 2 limits then yes both limits MUST converge.
so if you're lucky and get the limit that diverges you can just move on to other problems quicker.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top