Show the Symmetric group is generated by the set of transpositions (12) (n-1 n).

Click For Summary

Homework Help Overview

The discussion revolves around proving that the symmetric group S_n is generated by a specific set of transpositions, particularly focusing on the set {(1 2), (3 4), ..., (n-1 n)}. Participants are exploring the relationship between n-cycles and 2-cycles within the context of group theory.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • One participant attempts to show that any n-cycle can be expressed as a product of 2-cycles, while another participant questions the initial set of transpositions provided. There is a focus on using induction to demonstrate that any 2-cycle can be generated from the corrected set of transpositions.

Discussion Status

The discussion is ongoing, with participants actively refining their arguments and correcting initial misunderstandings about the transpositions. Some guidance has been offered regarding the use of induction to establish relationships between 2-cycles and the proposed generating set.

Contextual Notes

There appears to be some confusion regarding the correct set of transpositions needed for the proof, which has led to multiple interpretations of the problem. Participants are also considering the implications of the distance between indices in the 2-cycles.

Edellaine
Messages
11
Reaction score
0

Homework Statement


5.1: Prove that S_n is generated by the set {(1 2), (3 4),...,(n-1 n)}

Homework Equations


None that I know of

The Attempt at a Solution


Any element in S_n can be written as a product of disjoint n-cycles. So now I need to show any n-cycle can be written as a product of 2-cycles. So if my cycle is (a1 ... ak) = (a1 a2)(a1 a3)...(a1 ak).

So now I've shown S_n can be generated by 2-cycles in general. I'm not sure how to extend this to say that S_n is generated by the set above.
 
Physics news on Phys.org


You started your set off wrong. It's not {(12),(34),...}, it's {(12),(23),...}. Now you need to show any 2 cycle is generated by your set.
 


Oh, my bad. I wrote the set down wrong.

WTS: Any 2-cycle is generated by the set {(12)(23)...(n-1 n)}

So taking any 2-cycle (i j) where j > i (I'm going to work on the difference between j and i. I guess what follows is a sketch. I'll clean it up later.)

If j-i=1, then (i j) = (i i+1). (Probably want to induct on j-i)
Say the above is the base case, then we can assume its true for all (i j) where j-i \leq k (for strong induction), where k \geq1.
There for any (i j) with j-i = k+1, then (i i+1)(i+1 j) and j-(i+1) = j-i-1\leq k.
Then (i+1 j) is a product of 2-cycles of consecutive integers (as in the above set). Then by induction, so is (i j).

Then any (i j) in S_n is a product of consecutive integers. (Fin)
 


Edellaine said:
Oh, my bad. I wrote the set down wrong.

WTS: Any 2-cycle is generated by the set {(12)(23)...(n-1 n)}

So taking any 2-cycle (i j) where j > i (I'm going to work on the difference between j and i. I guess what follows is a sketch. I'll clean it up later.)

If j-i=1, then (i j) = (i i+1). (Probably want to induct on j-i)
Say the above is the base case, then we can assume its true for all (i j) where j-i \leq k (for strong induction), where k \geq1.
There for any (i j) with j-i = k+1, then (i i+1)(i+1 j) and j-(i+1) = j-i-1\leq k.
Then (i+1 j) is a product of 2-cycles of consecutive integers (as in the above set). Then by induction, so is (i j).

Then any (i j) in S_n is a product of consecutive integers. (Fin)

That could use some clean up. I'm having a hard time following it. The basic fact you need is just (j,j+1)(j,k)(j,j+1)=(j+1,k), right?
 
Last edited:

Similar threads

  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
3
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
4
Views
5K
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
8K