Show this equality of limits - cross products

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Homework Statement


Show that

\displaystyle\lim_{\underline{h}\to 0} \frac{\underline{c} \times \underline{h}}{\|\underline{h}\|} =0

where c and h are vectors and x denotes cross product.

Homework Equations





The Attempt at a Solution



No idea how to do this?
 
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Ted123 said:

Homework Statement


Show that

\displaystyle\lim_{\underline{h}\to 0} \frac{\underline{c} \times \underline{h}}{\|\underline{h}\|} =0

where c and h are vectors and x denotes cross product.

Homework Equations


The Attempt at a Solution



No idea how to do this?

I don't think it's true. Suppose the vectors are in R^3, with i,j,k the usual coordinate vectors. Let c = i, h = tj. (where t is a scalar)

Then

\left|\frac{c \times h}{|h|}\right| = \left|\frac{tk}{|tj|}\right| = \frac{|tk|}{|tj|} = \frac{|t|}{|t|} = 1

so the limit is certainly not zero as h approaches zero along the i coordinate axis. If the limit were zero, it would have to be zero no matter how h approaches zero.
 


What happens if you let

\vec c = \vec i,\, \vec h = \lambda \vec j

where \vec i,\vec j are the standard unit vectors?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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