Showing when a subset is an equality

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Homework Statement


In general, ##A \subseteq \mathcal{P} \bigcup A##. Under what conditions does equality hold?

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The Attempt at a Solution


I can't seem to figure this out. If ##A## has ##n## elements, then clearly ##| \bigcup A | \ge n##, which would mean that ##| \mathcal{P} \bigcup A | \ge 2^n##, right? In this case the cardinalities never seem to be the same, in which case equality can never hold.
 
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## \mathcal{P} \bigcup A ## and ##\bigcup \mathcal{P} A ## are different things.
 
mfb said:
## \mathcal{P} \bigcup A ## and ##\bigcup \mathcal{P} A ## are different things.
Oops. In both cases I meany ##\mathcal{P} \bigcup A##
 
What is ##\bigcup A##? The union of what, if A is a single object?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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