Signal and Systems: Verify the impulse response of this system

[SumDood_]

Homework Statement

Verify that the impulse response of this system is h(t) = e^(-2t)u(t)

Relevant Equations

Impulse response => x(t) = impulse

Verify that the impulse response of this system is $h(t) = e^{-2t}u(t)$ for the following system
$$\frac{dy(t)}{dt} + 2y(t) = x(t)$$

So this is what I did first,
$$
\begin{align}
\frac{dh(t)}{dt} + 2h(t) &= \delta (t) \\
\frac{d}{dt}e^{-2t}u(t) + 2e^{-2t}u(t) &= \delta (t) \\
-2e^{-2t}u(t) + 2e^{-2t}u(t) &= \delta (t) \\
0 &= \delta (t)
\end{align}
$$
Of course, my solution is wrong. Honestly, at the beginning, I didn't know what I am supposed to get that would verify that the impulse response of the system is $h(t) = e^{-2t}u(t)$.
So, first, what mistake did I make when simplifying after substituting $h(t)$ and $x(t)$?
Second, what form does the final statement need to take to actually verify the impulse response? Should I end up with a true statement?

 

[DaveE]

Homework Statement: Verify that the impulse response of this system is h(t) = e^(-2t)u(t)
Relevant Equations: Impulse response => x(t) = impulse

Verify that the impulse response of this system is $h(t) = e^{-2t}u(t)$ for the following system
$$\frac{dy(t)}{dt} + 2y(t) = x(t)$$

So this is what I did first,
$$
\begin{align}
\frac{dh(t)}{dt} + 2h(t) &= \delta (t) \\
\frac{d}{dt}e^{-2t}u(t) + 2e^{-2t}u(t) &= \delta (t) \\
-2e^{-2t}u(t) + 2e^{-2t}u(t) &= \delta (t) \\
0 &= \delta (t)
\end{align}
$$
Of course, my solution is wrong. Honestly, at the beginning, I didn't know what I am supposed to get that would verify that the impulse response of the system is $h(t) = e^{-2t}u(t)$.
So, first, what mistake did I make when simplifying after substituting $h(t)$ and $x(t)$?
Second, what form does the final statement need to take to actually verify the impulse response? Should I end up with a true statement?

$\frac{d}{dt}[e^{-2t}u(t)] \neq -2e^{-2t}u(t)$. Use the product rule, $u(t)$ is also a differentiable function of $t$.

 

[SumDood_]

$\frac{d}{dt}[e^{-2t}u(t)] \neq -2e^{-2t}u(t)$. Use the product rule, $u(t)$ is also a differentiable function of $t$.

Got the right solution, thanks!