- #1
Linday12
- 54
- 0
[SOLVED] Simple Acceleration Equation Help
g=-9.80 m/s^2
t= 3.85
vi= 0.00 m/s
d=?
d=vi(t) + (1/2)gt^2
d=0 + (1/2)(-9.80m/s^2)((3.85s)^2)
=-72.6
I'm trying to find the distance. So, this d represents displacement. Since in this case, this is also the distance, would there be any other work to show the sign change, since the d would be going from a vector to a scalar? Or should I have modified this equation beforehand to show d as a scalar, and not have taken into account the gravities negative?
By the way, sorry, this must seem like a trivial matter really not worth time, but I hate not understanding it down to the tiny details. Thank you very much!
g=-9.80 m/s^2
t= 3.85
vi= 0.00 m/s
d=?
d=vi(t) + (1/2)gt^2
d=0 + (1/2)(-9.80m/s^2)((3.85s)^2)
=-72.6
I'm trying to find the distance. So, this d represents displacement. Since in this case, this is also the distance, would there be any other work to show the sign change, since the d would be going from a vector to a scalar? Or should I have modified this equation beforehand to show d as a scalar, and not have taken into account the gravities negative?
By the way, sorry, this must seem like a trivial matter really not worth time, but I hate not understanding it down to the tiny details. Thank you very much!