Simple concept help: Pulley and Net Torque

AI Thread Summary
The discussion revolves around solving a physics problem involving a hollow sphere and a mass connected by a cord. The user attempts to calculate the angular acceleration of the sphere, the linear acceleration of the mass, and the tension in the cord using force and torque equations. They initially arrive at an incorrect solution due to sign errors in their equations. A suggestion is made to adjust the sign conventions for clarity, specifically to consider downward and clockwise directions as positive. Correcting these signs is crucial for arriving at the right answers in this type of problem.
john562
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Homework Statement


A ball (hollow sphere) of radius .11m and mass .444kg is mounted on a frictionless axle. A massless cord is wrapped around the ball supporting an object of mass .02kg. Find the angular acceleration of the wheel, linear acceleration of the object and tension in the cord.


Homework Equations





The Attempt at a Solution


\SigmaF=Fg+T=m*a
-.2+T=.02a

\Sigma\tau=F*r=I*\alpha
-T*.11=(.0036*a)/.11
T = -.2975*a

-.2 + .2975*a = .02*a
-.2 = -.2775a
.72 = a

That's what I tried, but it's wrong.
Can anyone help?
 

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john562 said:

Homework Statement


A ball (hollow sphere) of radius .11m and mass .444kg is mounted on a frictionless axle. A massless cord is wrapped around the ball supporting an object of mass .02kg. Find the angular acceleration of the wheel, linear acceleration of the object and tension in the cord.


Homework Equations





The Attempt at a Solution


\SigmaF=Fg+T=m*a
-.2+T=.02a
0.2 -T = .02a
\Sigma\tau=F*r=I*\alpha
-T*.11=(.0036*a)/.11
T*.11 = .0036a/.11
T = -.2975*a
T = .2975a
-.2 + .2975*a = .02*a
-.2 = -.2775a
.72 = a

That's what I tried, but it's wrong.
Can anyone help?
You must watch your signage. The acceleration is downwards. Choose the downward and clockwise directions as positive, for compatability and simplicity.
 
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