Is 0.132 Hartrees/Bohr^2 Correctly Converted to J/m^2?

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The conversion of 0.132 Hartrees/Bohr^2 to J/m^2 involves multiplying by 4.36 x 10^(-18) J/Hartree and dividing by (5.29 x 10^(-11))^2 m^2/Bohr^2. After performing the calculations, the result is approximately 205.7 J/m^2. The initial uncertainty about the conversion process was addressed, confirming the method used. Overall, the conversion appears to be correct based on the provided calculations.
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Can someone please confirm whether I've done the following conversion correctly?

What does 0.132 Hartrees/Bohr^2 convert to in units of J/m^2?
 
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Not knowing what you did we can't say if you did it right.
 
Borek said:
Not knowing what you did we can't say if you did it right.

Ugh. You're right...I can't believe I forgot to post that.

I took 0.132 and multiplied by 4.36 x 10^(-18) J/Hartree, then divided by (5.29 x 10^(-11))^2 m^2/Bohr^2. This gives me something like 205.7 J/m^2.
 
Looks OK to me.
 

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