Simple Derivation Maxwell Equations

kiwi101
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Homework Statement


Derive the 2 divergence equations from the 2 curl equations and the equation of continuity.


Homework Equations


∇°D=ρ
∇°B = 0
∇xE = -∂B/∂t
∇xH = J + ∂D/∂t
∇°J = -∂ρ/∂t (equation of continuity)


The Attempt at a Solution


1)∇xE = -∂B/∂t
∇°(∇xE) = ∇°(-∂B/∂t)
0 =∇°(-∂B/∂t) (divergence of curl of vector field is 0)
I'm stuck now I don't know what to do


2)∇xH = J + ∂D/∂t
∇°(∇xH) = ∇°(J + ∂D/∂t)
0 =-∂ρ/∂t + ∇°∂D/∂t
Once again I am stuck here too


Please guide me guys
 
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kiwi101 said:

The Attempt at a Solution


1)∇xE = -∂B/∂t
∇°(∇xE) = ∇°(-∂B/∂t)
0 =∇°(-∂B/∂t) (divergence of curl of vector field is 0)
I'm stuck now I don't know what to do

See this and apply it to your situation where one of the variables is time.
 
You're on the right track, just remember that spatial derivitives (like the divergence) commute with the time derivitives.
 
So
0 = -∂/∂t(∇°B)
Does the -∂/∂t and the divergence cancel? Or do they make a second order derivative?
 
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If the partial derivative with respect to time of a function of space and time is zero at all points of space, then what can you conclude about the function?

Think of ##\small \nabla \cdot \bf{B}## as some function of space and time.
 
That means that the function is constant regardless of time at all points of space
 
kiwi101 said:
That means that the function is constant regardless of time at all points of space

Right, so ##\small \nabla \cdot \bf{B}## does not depend on time. It can be a function of space only.

Strictly speaking, I think this is as far as you can go mathematically. But can you add a reasonable physical argument that will allow you to go further?
 
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oh okay
thank you so much guys!
 
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