A block of mass 2kg oscillates on the end of a spring in SHM with a period of 20ms. The position of the block is given by: x=(1.0cm)cos(wt+2pi). Another block of mass 4kg slides toward the oscillating block with velocity of 6m/s. The two blocks undergo a completely inelatic collision at time t=5.0ms.(adsbygoogle = window.adsbygoogle || []).push({});

a)what is the amplitude of oscllaltion after collision?

I know momentum is conserved in the collision and time t=.005 secons, the velocity of the oscillating block is O. So I got V(final)=4m/s.

But I am not sure how to account for this with the spring force to get the final amplitude.

b) What is the frequency of the resulting SHM?

without A, I dont think I can do this part, so I havent tried yet...

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# Homework Help: Simple Harmonic motion and collisions

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