Simple Harmonic Motion: Pendulum of Clock Replaced by Spring-Mass

  • Thread starter hermy
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  • #1
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Homework Statement



The pendulum of a clock is replaced by a spring-mass system with the spring having spring constant 0.1 N/m. What mass should be attached to the spring?


Homework Equations



T=2 pi (m/k)1/2

The Attempt at a Solution



1 = 2 pi (m/0.1)1/2
1 = 4 pi2 m/0.1

solving this, m= 25 grams

The answer is supposed to be 10 grams. What is wrong in my solution?

Thanks for the help.
 

Answers and Replies

  • #2
Doc Al
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1 = 2 pi (m/0.1)1/2
1 = 4 pi2 m/0.1

solving this, m= 25 grams
You're off by a factor of 10.

The answer is supposed to be 10 grams. What is wrong in my solution?
You are assuming that the period is 1 second. Was that specified in the problem? (Was information given about the pendulum?)
 
  • #3
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I'm sorry, this question turned out to be quite easy. I came to know that the time period of a pendulum clock is 2s. Putting all this together, the answer does come out. Thanks for the help.
 

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