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Simple Harmonic Motion Problems

  1. Nov 28, 2011 #1
    I am having a hard time solving for k in the equation
    T =
    2 x pi sq. rt. (m/k)

    I know this is simple algebra but its keeping me from solving this.
     
  2. jcsd
  3. Nov 28, 2011 #2

    gneill

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    Staff: Mentor

    What happens if you square both sides of the equation?
     
  4. Nov 28, 2011 #3
    the sq rt goes away on the side with 2 x pi (m/k) and then T^2. so T^2 = 2pi x (m/k) now can be simplified into k = (2pi x m) / T^2?
     
  5. Nov 28, 2011 #4

    gneill

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    Staff: Mentor

    No, you can't just square part of a side. The [itex] 2 \pi [/itex] has to be squared, too.
     
  6. Nov 28, 2011 #5
    T^2 = 2pi^2 x (m/k) then k = 2pi ^2 x m/ T^2
     
  7. Nov 28, 2011 #6

    gneill

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    Staff: Mentor

    What about the 2? You must do the same operation to all parts of a given side if the equation is to remain balanced.
     
  8. Nov 28, 2011 #7
    k =((2pi)^2 x m)/T^2
     
  9. Nov 28, 2011 #8

    gneill

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    Staff: Mentor

    That looks better!

    If you want to clean it up a bit, you could make it:
    [tex] k = \left( \frac{2 \pi}{T} \right)^2 m[/tex]
     
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