- #1

- 4

- 0

T =

2 x pi sq. rt. (m/k)

I know this is simple algebra but its keeping me from solving this.

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- Thread starter 03MGCobra
- Start date

- #1

- 4

- 0

T =

2 x pi sq. rt. (m/k)

I know this is simple algebra but its keeping me from solving this.

- #2

gneill

Mentor

- 20,925

- 2,866

T =

2 x pi sq. rt. (m/k)

I know this is simple algebra but its keeping me from solving this.

What happens if you square both sides of the equation?

- #3

- 4

- 0

- #4

gneill

Mentor

- 20,925

- 2,866

No, you can't just square part of a side. The [itex] 2 \pi [/itex] has to be squared, too.

- #5

- 4

- 0

T^2 = 2pi^2 x (m/k) then k = 2pi ^2 x m/ T^2

- #6

gneill

Mentor

- 20,925

- 2,866

T^2 = 2pi^2 x (m/k) then k = 2pi ^2 x m/ T^2

What about the 2? You must do the same operation to

- #7

- 4

- 0

k =((2pi)^2 x m)/T^2

- #8

gneill

Mentor

- 20,925

- 2,866

k =((2pi)^2 x m)/T^2

That looks better!

If you want to clean it up a bit, you could make it:

[tex] k = \left( \frac{2 \pi}{T} \right)^2 m[/tex]

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