- #1

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I dont know how to get the period from this equation? Can anyone lead me in the right direction, please? Thanks! ~Dave W.

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- Thread starter NanoTech
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- #1

- 63

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I dont know how to get the period from this equation? Can anyone lead me in the right direction, please? Thanks! ~Dave W.

- #2

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[tex] x = Acos(\omega{t} + \phi)[/tex]

where the quantities are as you stated.

Now, I can tell you that [tex]\omega[/tex] (the angular frequency) is equal to [tex]2\pi{f}[/tex], where f is the frequency (number of oscillations per second).

From that, can you find the period?

- #3

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Kinda. I see that [tex] f = \frac{1}{T}[/tex]

So, from that, I can write:

[tex] x = Acos(\frac{2\pi}{T}(t) + \phi)[/tex]

Then, I solve for T:

but i've now introduced an "x" and a "t" into the problem, where do i go from here?

So, from that, I can write:

[tex] x = Acos(\frac{2\pi}{T}(t) + \phi)[/tex]

Then, I solve for T:

but i've now introduced an "x" and a "t" into the problem, where do i go from here?

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- #4

Doc Al

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Right!NanoTech said:Kinda. I see that [tex] f = \frac{1}{T}[/tex]

Don't do that! Instead write the equation for ω (which is given) in terms of T. (I know you can do it, since that's what you just did to rewrite that equation.)So, from that, I can write:

[tex] x = Acos(\frac{2\pi}{T}(t) + \phi)[/tex]

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