Simple Harmonic Motion Tuning Fork Question

AI Thread Summary
A tuning fork vibrating at 264 Hz has prong tips that move 1.66 mm from the center, which indicates the amplitude. The maximum speed (Vmax) of the prong tips can be calculated using the formula Vmax = omega * A, where omega is the angular frequency. The user initially struggled with the calculations but realized that T (period) can be derived from the frequency (f) as T = 1/f. After some confusion with the calculations, the user acknowledged a potential error in their calculator input. The discussion highlights the importance of correctly applying formulas and understanding amplitude in simple harmonic motion.
ninjagowoowoo
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Q:
A tuning fork vibrates at a frequency of 264 Hz and the tip of each prong moves 1.66 mm to either side of center. Calculate the maximum speed of the tip of a prong.

So far I've found that Vmax = omega*A, but I don't know how to find A. Am I going in the wrong direction? Or is there a way to find A that I don't know about yet..?
 
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ninjagowoowoo said:
... the tip of each prong moves 1.66 mm to either side of center.
That's the amplitude.
 
Oh haha, I knew it must've been something stupid, thanks.
 
Ok so I figured that Vmax would be omega*A, but it isn't correct. I know that
v=-omega*A*sin(omega*t) (yeah I need to learn how to write equations better)

so I assumed that in the problem, it's basically an initial value, so t=0. So that would leave v=omega*A.

From this I got Vmax = (2pi/T)(A)
and T=1/f

so Vmax = (2pi/(1/f))(A)

I guess this is incorrect. Oh and I didnt forget to convert mm to m. Any pointers?
Thanks
 
woops nevermind... I must have entered it in my calculator wrong haha sorry. Thanks for the help Al.
 

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