Simple harmonic motion with an amplitude

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Homework Help Overview

The discussion revolves around a problem in simple harmonic motion involving a block attached to a spring. The spring constant is provided, along with the amplitude of motion and a measured speed at a specific position. Participants are tasked with calculating the mass of the block, the period of motion, and the maximum acceleration.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore using energy conservation principles and the relationship between speed, spring constant, and mass. There is an attempt to derive the mass using the provided formulas, but some participants express uncertainty about their calculations and seek clarification on the correct approach.

Discussion Status

The discussion is active, with participants offering different perspectives on how to approach the problem. Some guidance has been provided regarding the application of conservation of energy, and there is a request for more detailed calculations to identify mistakes. Multiple interpretations of the problem are being explored.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the information they can use or the methods they can apply. There is an emphasis on understanding the principles of energy interchange in simple harmonic motion.

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Homework Statement


A block of unknown mass is attached to a spring with a spring constant of 5.50 N/m and undergoes simple harmonic motion with an amplitude of 12.5 cm. When the block is halfway between its equilibrium position and the end point, its speed is measured to be 25.0 cm/s.

(a) Calculate the mass of the block.
(b) Calculate the period of the motion.
(c) Calculate the maximum acceleration of the block.


Homework Equations


Vmax = sqrt(k/m)A
T= 2pi/w
a_max = kA/m



The Attempt at a Solution


so i thought i would use the first formula i stated to find the mass of the block
but apparently I am wrong.
can someone please help me get started.
thanks
 
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Well the total energy of the system is given by 1/2 kA2 and throughout the motion this is interchanged between elastic potential and kinetic energy. So halfway between the max point and equilibrium, how far does the spring stretch? Can you now apply a conservation of energy to get the mass?
 


Show your calculations to see where you have made mistake.
 


well what i did was
vmax = sqrt(k/m)A
(v^2/A^2)m = k
so
m = kA^2/v^2 but i guess this is wrong

so do i use something like 1/2kA^2 = 1/2mv^2 ?
 

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