Maximizing Speed in Simple Harmonic Motion | SHM Homework Solution

AI Thread Summary
To double the maximum speed of simple harmonic motion (SHM), one can increase the amplitude (A) by a factor of two while keeping the spring constant (k) and mass (m) constant. The maximum speed is calculated using the formula v_max = sqrt{k/m}A. Since maximum speed occurs at the equilibrium point, doubling the amplitude directly results in doubling the maximum speed. This approach effectively demonstrates the relationship between amplitude and speed in SHM.
recklessid
Messages
1
Reaction score
0

Homework Statement



How could you double the maximum speed of a SHO?

Homework Equations



v_max = sqrt{k/m}A

The Attempt at a Solution



The speed is at its maximum when it's period is complete and is passing through its equilibrium point. k and m can be kept at the same. BUt if we double the value of A, then v_max should also be doubled as well.

Is this right?
 
Physics news on Phys.org
You are correct--double the amplitude and you double the max speed.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...

Similar threads

Back
Top