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Simple Harmonic Motion

  • #1
An object attached to a spring (k = 30 N/m) has a velocity of 2.5 m/s when it is .55 m from equilibrium, and has a period of 2.45 s.

After doing other parts I found the mass to be 4.561 kg, the total enegy of the system to be 18.79 J, the amplitude to be 1.12 m, and the maximum speed to be 2.86 m/s.

The part that I am stuck on/don't understand is: At what displacement is the speed maximized?

What am I supposed to do? What formulas am I supposed to use?
 

Answers and Replies

  • #2
dextercioby
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Soaring Crane said:
An object attached to a spring (k = 30 N/m) has a velocity of 2.5 m/s when it is .55 m from equilibrium, and has a period of 2.45 s.

After doing other parts I found the mass to be 4.561 kg, the total enegy of the system to be 18.79 J, the amplitude to be 1.12 m, and the maximum speed to be 2.86 m/s.

The part that I am stuck on/don't understand is: At what displacement is the speed maximized?

What am I supposed to do? What formulas am I supposed to use?
I made use of a simpler version of it in the other thread.
It is:
[tex] v(t)=\omega A\cos(\omega t+\phi) [/tex]
,from where u must find the 'cos'.From the 'cos',it's easy to find the 'sine' which is gonna be needed to compute the "x".
[tex] x(t)=A\sin(\omega t+\phi) [/tex]

Daniel.
 

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