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Simple Harmonic Motion

  1. Jan 3, 2005 #1
    An object attached to a spring (k = 30 N/m) has a velocity of 2.5 m/s when it is .55 m from equilibrium, and has a period of 2.45 s.

    After doing other parts I found the mass to be 4.561 kg, the total enegy of the system to be 18.79 J, the amplitude to be 1.12 m, and the maximum speed to be 2.86 m/s.

    The part that I am stuck on/don't understand is: At what displacement is the speed maximized?

    What am I supposed to do? What formulas am I supposed to use?
     
  2. jcsd
  3. Jan 3, 2005 #2

    dextercioby

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    I made use of a simpler version of it in the other thread.
    It is:
    [tex] v(t)=\omega A\cos(\omega t+\phi) [/tex]
    ,from where u must find the 'cos'.From the 'cos',it's easy to find the 'sine' which is gonna be needed to compute the "x".
    [tex] x(t)=A\sin(\omega t+\phi) [/tex]

    Daniel.
     
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