Simple Ideal Gas Law but i keep getting it wrong

AI Thread Summary
The discussion revolves around solving the ideal gas law equation PV=nRT to find the volume (V) given pressure (P), number of moles (n), gas constant (R), and temperature (T). The user initially calculated V as 0.027 L but received an error regarding significant figures. It was clarified that the conversion from cubic meters to liters was incorrectly done, as 1 m³ equals 1000 liters, not 1,000,000. After addressing the conversion issue, the user successfully arrived at the correct answer. Accurate unit conversion and attention to significant figures are crucial in solving gas law problems.
acg7160
Messages
11
Reaction score
0

Homework Statement



P=1.5 atm; n=2 mols, R=8.314; T=250 K; V=?

Homework Equations


PV=nRT
i converted p into Pa and got 151987.5 Pa.


The Attempt at a Solution


I plugged in all of the numbers and got V=0.027 L but it keeps saying my answer is wrong. It says answer for 2 sig figs. I am not sure what I am doing wrong. Help please?
 
Physics news on Phys.org
your answer is in m^{3}. You need to convert to liters. Hint:

<br /> 1 \, \mathrm{L} = 1 \, \mathrm{dm}^{3}<br />
 
acg7160 said:
I plugged in all of the numbers and got V=0.027 L but it keeps saying my answer is wrong. It says answer for 2 sig figs. I am not sure what I am doing wrong. Help please?
I think something went wrong with your conversion from m3 to liters. There are 1000 liters in a m3 (not 1 000 000 -- that would be ml per m3). :wink:

[Edit: Oops, I see Dickfore beat me to the answer.]
 
Thanks I got it right!
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Ideal Gas Law and Pressure at 80°C
Replies
2
Views
3K
Calculations using the Ideal Gas Law
Replies
2
Views
2K
Finding both temperature and the amount of gas added
Replies
6
Views
1K
Incompatibility between ideal gas equations of state
Replies
2
Views
1K
Find temperature of a U-shaped Tube
Replies
9
Views
729
Closed cycle of an ideal gas
Replies
3
Views
1K
Why is temperature constant after gas has expanded?
Replies
33
Views
2K
Ideal Gas Law: Question about a compressor exam question
Replies
4
Views
2K
Work done during quasi-static, isothermal expansion from P_i to P_f
Replies
4
Views
2K
What Is the Highest Temperature Reached in the Ideal Gas Cycle?
Replies
4
Views
3K

Hot Threads

Recent Insights

Back
Top