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## Homework Statement

Is there a simple way to evaluate

S x^5 / [rt(x^2-ax)] dx ?

That is, the indefinite integral of (x^5) / [square root of (x^2-ax)].

## The Attempt at a Solution

My idea was to rewrite it as x^(9/2) / [rt(x-a)] and then do the substitution u = rt(x-a).

Then you get

S 2(u^2+a)^(9/2) du

But this too is difficult to evaluate.

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