- #1
DeanBH
- 82
- 0
i know how to integrate.
but why is 3/x 3 log x3x^-1 3 x^0 X^0 = 1 3*1 = 3.
i know I'm ignoring the divide by zero
why does log come into it.
4e^(1/2) I am messing this one up as well.4e^(3/2) / (3/2)
= 8/3e^(3/2) that's like as far as i get it.
somehow the answers have it at 8e^1/2
can anyone explain how that is so
but why is 3/x 3 log x3x^-1 3 x^0 X^0 = 1 3*1 = 3.
i know I'm ignoring the divide by zero
why does log come into it.
4e^(1/2) I am messing this one up as well.4e^(3/2) / (3/2)
= 8/3e^(3/2) that's like as far as i get it.
somehow the answers have it at 8e^1/2
can anyone explain how that is so
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