Simple kinematics question i think i am right just need to confirm

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A ball starts rolling down a ramp from rest with constant acceleration, moving 1 foot in the first second. The initial assumption that acceleration is zero is incorrect, as the ball would not move if that were the case. The correct approach involves using the equation delta x = vit + 1/2at^2 to determine the distance traveled in subsequent seconds. The discussion reveals confusion about calculating acceleration, with suggestions that it could be 1 ft/s² based on the distance covered in the first second. Ultimately, the calculations indicate that the acceleration is not simply 1 ft/s², and further clarification is needed for accurate results.
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Homework Statement


At t=0 a ball, initially at rest, starts to roll down a ramp with constant acceleration. You notice it moves 1 foot between t=0 seconds and t = 1 second.
How far does it move between t = 1 second and t = 2 seconds

Homework Equations


delta x=vit+1/2at2? since it is constant speed wouldn't acceleration be 0?

The Attempt at a Solution


it seems like it would be 1 foot right?
= 1(1)+1/2(0)(1)2
delta x=1foot?
 
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No the acceleration would not be zero. If it were zero, then the ball would not move.

ihatecats2014 said:

Homework Statement


At t=0 a ball, initially at rest, starts to roll down a ramp with constant acceleration. You notice it moves 1 foot between t=0 seconds and t = 1 second.

Using this information and the same relevant equations, what is the acceleration? (Remember, initially at rest means no initial velocity)
 
rock.freak667 said:
No the acceleration would not be zero. If it were zero, then the ball would not move.
Using this information and the same relevant equations, what is the acceleration? (Remember, initially at rest means no initial velocity)

would the acceleration be 1? because it went 1 foot in the elapsed time of 1 sec?

then
=0(1)+1/2(1)(1)^2
delta x equals 1/2 foot
this is wrong. i need a hint please

or if the time is 2sec the distance would then be 2 foot. but i think that is still wrong
 
ihatecats2014 said:
would the acceleration be 1? because it went 1 foot in the elapsed time of 1 sec?

Your equation is x=ut+0.5at2 (u= initial velocity)

Using this equation a≠1 ft/s2.
 
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