Finding the Equilibrium Price and Quantity for a Simple Linear Equation?

AI Thread Summary
The discussion focuses on finding the equilibrium price and quantity using the equations P = -50Qd + 80 and P = 2Qs + 10. The equilibrium condition requires setting quantity demanded (Qd) equal to quantity supplied (Qs). The attempted solution shows a calculation leading to an equilibrium quantity of 70/52, but there is confusion regarding the accuracy of the equations provided. Participants express concern about the coefficients in the equations, particularly questioning whether the second equation should include 2Qs or 20Qs. Clarification on the equations is necessary to ensure the correct equilibrium is determined.
vitaminZ
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Homework Statement


P = -50Qd + 80
P = 2Qs + 10

P = Price
Qd = Quantity demanded
Qs = Quantity supplied

Find the equilibrium Price and Quantity.


Homework Equations


Qd = Qs
(equilibrium)

The Attempt at a Solution


Qd = Qs
Q

Since they both equal to P

-50Q + 80 = 2Q + 10 [-2Q]
-52Q + 80 = 10 [-80]
-52Q = -70 [/52Q]
Q = 70/52
Equilibrium Quantity = 70/52

I don't know why this is wrong?
 
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I came up with the same answer. I didn't major in economics, though...I just assumed (because it sounds right) that you are right, that equilibrium occurs when the supply = demand.
 
Are you sure that you are starting with the right equations? Have you given the problem exactly as it appears in your text or wherever you got it? I'm especially concerned with your Qd equation with the -50 coefficient.
 
vitaminZ said:

Homework Statement


P = 2Qs + 10
are you sure that this equation has 2Qs or should it have 20Qs.
 
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
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