Simple (or should be) Trigonomic question

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AI Thread Summary
The discussion revolves around converting latitude and longitude values into Cartesian coordinates for an object moving on the Earth's surface, and then back into latitude and longitude. The user successfully converts lat/long to a position vector but struggles with the reverse conversion. Initially, they mistakenly believed that secant and cosine were inverse operations, which led to confusion. After some reflection, they realized that arccos is the correct inverse function for cosine. Ultimately, the user resolved their issue and confirmed that their conversions are now functioning correctly.
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Homework Statement



I'm making a program that tracks an object moving along the surface of a sphere (earth). I'm using a set of Cartesian coordinates who origin is the center of the Earth and Z directed through the north pole, X the greenwich meridian at the equator, and Y is 90 degrees to everyone else.

Given a Lat/Long value I can convert into a position vector by doing:

phi = (90 - lat)*pi/180
theta = long*pi/180

vector.x = sin(phi)*cos(theta)
vector.y = sin(phi)*sin(theta)
vector.z = cos(phi)

After moving my object around I need to convert it back into lat / long. At the moment I'm just trying to take a position in Lat/long, convert it into my position vector, draw it on a sphere , then convert it back.

I know my conversion TO the position vector is working properly since it points to the right spot on a sphere. What I can't get right is the conversion FROM the vector back to lat long.

Homework Equations


See above.


The Attempt at a Solution



I thought I could find phi from the Z component, then solve X and Y simultaneously for theta. So since Z = cos(phi), I thought easy phi = 1/cos(Z).

Only that didn't work. Sat down, thought for a bit, played around with cos and sec, and realized cos and sec aren't inverse operations (which I thought for sure they were) so sec(cos(a)) != a.

There's a simple little rule for finding going from A = cos(angle), to an expression for the angle, when you know A. Can someone please tell me what it is ? I've spent hours on something I thought I learned back in Highschool !
 
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Is there a reason you aren't using spherical coordinates instead of cartesian coordinates? Seems like you're making it extra hard on yourself.

Here are some trig notes from wikipedia if they help:

http://en.wikipedia.org/wiki/Trig

.
 
We were told to use Cartesian, not spherical. Gonna have another read through the wiki page, its got to be there somewhere.
 
I worked it out. Turns out sec is the reciprocal of cos, arccos is the inverse function. I'm annoyed I forgot something so basic, but at least its all working now.
 
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