Simple pendulum in different situations

AI Thread Summary
The discussion centers on the effects of filling a pendulum bob with water versus freezing it, questioning whether these changes affect the pendulum's time period. Participants agree that if the bob is completely filled with water and friction is neglected, the time period remains unchanged due to the uniform distribution of mass. The conversation highlights that the pendulum's period is independent of mass, as long as the conditions are controlled. However, there is some debate regarding the implications of water sloshing and the potential for chaotic behavior in a partially filled bob. Ultimately, under the specified conditions, the time period of the pendulum does not vary with the state of the water.
Adikshith Ojha
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Say there is a pendulum which is suspended by a massless thread or rod or whatever, the bob is spherical and hollow. Now consider 2 cases 1) the pendulum is completely filled with water 2) the water inside freezes. will there be a difference in the time periods? If so, why?
 
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My first instinct is that not only will the period be different, but the behavior may even become chaotic when the water is liquid, like a double-pendulum.
The water sloshing inside the bob would add an extra degree of freedom, like a second pendulum.

Unless the bob is completely filled with water. I wouldn't expect a difference in that case.
 
If you disregard the friction of the water, isn't the water stationary? Also, if the water freezes, the bob has to expand right? since the period of a pendulum is 2pisqrt(l/g), there would be no difference. However, if the bob expands, that would slightly change l.
 
Well, I guess I should've stated some more conditions (being a student, I take them for granted) there is no friction due to water and neglect any changes in volume. Anyway, both of you say that there is Jo change, that must be it then.
 
Equation needed: T=2π√(L/G). If the water is uniformly distributed and also fills up the entire sphere (to avoid sloshing which changes this whole problem), and we're ignorning friction, expansion, etc... Then no there should be no difference. The bob's center of mass remains in the center of the water (liquid/ice) as you can treat a sphere filled completely with water as a "solid" mass (ignoring the complicated stuff as this appears to).
 
Exactly what the previous poster mentioned. Because of your given constraints, and not a real world scenario, the Pendulum is mass independent. Therefore, I could fill it up with hot sauce, and the answer would be the same.
 
MidgetDwarf said:
Exactly what the previous poster mentioned. Because of your given constraints, and not a real world scenario, the Pendulum is mass independent. Therefore, I could fill it up with hot sauce, and the answer would be the same.
I think you need to clarify this. Pendulum is not mass independent.
 
just dani ok said:
I think you need to clarify this. Pendulum is not mass independent.
the period of the pendulum is mass independent.
 
MidgetDwarf said:
the period of the pendulum is mass independent.
sorry, my mistake.
 
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