1. The problem statement, all variables and given/known data A simple pendulum consists of a point mass m suspended from a fixed point by a weightless rigid rod of lengh l. The kinetic energy = 1/2*m*l^2*(dθ/dt)^2 The potential energy = -m*g*l*cosθ Calculate the time averages of the kinetic and potential energies over one cycle, AND compare them with the total energy of the system. 2. Relevant equations (d^2θ/dt^2) + (g/l)sinθ = 0 ∴ w = √(g/l) τ = 2∏/ω 3. The attempt at a solution T = 1/2ml^2 (ω)^2 T = 1/2mlg U = -mglcos(wt) U = -mglcos(√(g/l) * (2∏√l/g)) U = -mglcos(2∏) U = -mgl So 2T + U = 0 Is this the correct answer? Because I thought T should = U?