Simple Projectile Motion of ball

AI Thread Summary
The discussion centers on calculating the initial speed of a ball thrown horizontally from a 58 m tall building that lands 35 m away. The poster initially misidentified the vertical and horizontal distances, using 35 m as the height instead of 58 m. Correcting this, the vertical distance should be 58 m, and the horizontal distance is 35 m. The time of flight is recalculated based on the correct height, leading to a different initial speed. Accurate identification of distances is crucial for solving projectile motion problems effectively.
RedBurns
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Can someone tell me what I'm doing wrong here:

A ball is thrown horizontally from the roof of a building 58 m tall and lands 35 m from the base. What was the ball's initial speed?

X0= 0m Y0= 0m
X= 58 m Y= 35 m
Vx=? Vy=0 m/s
Ax=0 m/s/s Ax=-9.8 m/s/s
T=?

35=0+0T-.5(-9.8)T^2
T=2.6 s

58=0+Vx(2.6)
Vx= 22 m/s <----------I know this is wrong
 
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RedBurns said:
Can someone tell me what I'm doing wrong here:

A ball is thrown horizontally from the roof of a building 58 m tall and lands 35 m from the base. What was the ball's initial speed?

X0= 0m Y0= 0m
X= 58 m Y= 35 m
Vx=? Vy=0 m/s
Ax=0 m/s/s Ax=-9.8 m/s/s
T=?

35=0+0T-.5(-9.8)T^2
T=2.6 s

58=0+Vx(2.6)
Vx= 22 m/s <----------I know this is wrong

You've got your distances reversed! The building is 58m tall- that's the vertical distance: Y= 58m. The ball went 35 m horizontally: X= 35m
 
Thanks! I should have known it was something like that after cheking my math so any times
 
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