- #1

trajectory28

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## Homework Statement

A projectile is fired from the origin down an inclined plane that makes an angle, b, with the horizontal. The angle of elevation of the gun and the initial speed of the projectile are a and V, respectively.

Show that the angle of elevation, a, that will mazimize the downhill range is the angle halfway between the plane and the vertical.

## Homework Equations

I've already found the standard parametric equations of the trajectory as a function of time, t, below:

x(t)=(Vcos(a))t and y(t)=(Vsin(a))t - .5gt^2

## The Attempt at a Solution

I've already found the downhill range to be:

[(Vcos(a))t]/cos(b)

and if the angle that maximizes the downhill range is indeed the angle halfway between the plane and the vertical, then:

(b+(pi/2))/2 = a + b

a = pi/4 - b/2

I just have no idea where to go after this, I've been trying to figure out a way to represent the time, t, at which the particle strikes the downhill plane as a function of V, a, and b. All has been to no avail so your guidance is much appreciated!